Find an ordered pair \( (x, y) \) that is a solution to the equation. \[ \begin{array}{l}3 x+y=4 \\ (x, y)=0 .\end{array} \]

Let's solve the equation \(3x + y = 4\) for different values of \(x\) to find an ordered pair \((x, y)\). 1. **Choose a value for \(x\)**: Let's start with \(x = 0\): \[ 3(0) + y = 4 \implies y = 4 \] This gives us the ordered pair \((0, 4)\). 2. **Choose another value for \(x\)**: Now, let's try \(x = 1\): \[ 3(1) + y = 4 \implies 3 + y = 4 \implies y = 1 \] This gives us another ordered pair \((1, 1)\). Now we have two possible solutions: \((0, 4)\) and \((1, 1)\). You can choose any of these pairs as a solution to the equation!