Find the sum. 1) \( 2 \frac{1}{2}+1 \frac{1}{3}= \)

To find the sum of \( 2 \frac{1}{2} + 1 \frac{1}{3} \), first convert these mixed numbers into improper fractions. For \( 2 \frac{1}{2} \): \[ 2 \frac{1}{2} = 2 \times 2 + 1 = 4 + 1 = 5 \quad \text{so, } 5/2 \] For \( 1 \frac{1}{3} \): \[ 1 \frac{1}{3} = 1 \times 3 + 1 = 3 + 1 = 4 \quad \text{so, } 4/3 \] Now, we need to add \( \frac{5}{2} + \frac{4}{3} \). To do that, we should find a common denominator, which is 6 in this case. Convert \( \frac{5}{2} \): \[ \frac{5}{2} = \frac{5 \times 3}{2 \times 3} = \frac{15}{6} \] Convert \( \frac{4}{3} \): \[ \frac{4}{3} = \frac{4 \times 2}{3 \times 2} = \frac{8}{6} \] Now add them together: \[ \frac{15}{6} + \frac{8}{6} = \frac{15 + 8}{6} = \frac{23}{6} \] Thus, the sum of \( 2 \frac{1}{2} + 1 \frac{1}{3} = \frac{23}{6} \) or \( 3 \frac{5}{6} \) when converted back to a mixed number.