For maximum benefit during exercise, one's heart rate should increase by \( 50 \% \) to \( 85 \% \) above resting heart rate. (a) For a woman with a resting heart rate of 76 bpm , what would her heart rate be if she increased it by \( 75 \% \) during exercise? (b) A man with a resting heart rate of 88 bpm increased it to 132 bpm during exercise. By what percent did he increase his resting heart rate? (a) The woman's heart rate would be \( \square \mathrm{bpm} \). (Type a whole number or an exact decimal. If the decimal does not terminate, round to the nearest whole number.)

To calculate the woman's heart rate when increased by 75%, we take her resting heart rate of 76 bpm and first calculate the increase: 1. Calculate 75% of 76 bpm: \( 0.75 \times 76 = 57 \text{ bpm} \) 2. Add this increase to her resting heart rate: \( 76 + 57 = 133 \text{ bpm} \) So, the woman's heart rate would be \( 133 \mathrm{bpm} \). For the man with a resting heart rate of 88 bpm who increased it to 132 bpm, we can find the percent increase as follows: 1. Find the increase: \( 132 - 88 = 44 \text{ bpm} \) 2. Calculate the percent increase relative to the resting heart rate: \( \left( \frac{44}{88} \right) \times 100 = 50\% \) Thus, the man increased his resting heart rate by \( 50\% \).