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The start of a quadratic sequence is shown below. By first working out the \( n^{\text {th }} \) term rule, calculate the \( 10^{\text {th }} \) term of the sequence.

Ask by Pearson Norris. in the United States
Feb 04,2025

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Answer

To find the \( 10^{\text{th}} \) term of a quadratic sequence, first determine the \( n^{\text{th}} \) term formula using the initial terms. Once you have the formula, plug in \( n = 10 \) to find the term.

Solution

It appears that the sequence you're referring to wasn't included in your message. To determine the \( n^{\text{th}} \) term of a quadratic sequence and subsequently calculate the \( 10^{\text{th}} \) term, I'll need the initial terms of the sequence. **Here's how you can proceed once you have the sequence:** 1. **Identify the First Few Terms:** Let's assume the sequence starts with the terms \( a_1, a_2, a_3, \ldots \). 2. **Calculate the First Differences:** \[ d_1 = a_2 - a_1 \] \[ d_2 = a_3 - a_2 \] \[ \vdots \] 3. **Calculate the Second Differences:** \[ \Delta_1 = d_2 - d_1 \] \[ \Delta_2 = d_3 - d_2 \] \[ \vdots \] For a quadratic sequence, the second differences (\( \Delta \)) should be constant. 4. **Formulate the \( n^{\text{th}} \) Term:** The general form of a quadratic sequence is: \[ a_n = an^2 + bn + c \] Using the first few terms, set up equations to solve for constants \( a \), \( b \), and \( c \). 5. **Solve for \( a \), \( b \), and \( c \):** Substitute the values from the initial terms into the general formula to create a system of equations and solve for the constants. 6. **Calculate the \( 10^{\text{th}} \) Term:** Once you've determined \( a \), \( b \), and \( c \), plug \( n = 10 \) into the formula to find the \( 10^{\text{th}} \) term. **Example:** Suppose the sequence is: 3, 7, 13, 21, ... 1. **First Differences:** \[ 7 - 3 = 4 \] \[ 13 - 7 = 6 \] \[ 21 - 13 = 8 \] 2. **Second Differences:** \[ 6 - 4 = 2 \] \[ 8 - 6 = 2 \] (Constant second difference of 2) 3. **Form Equations:** \[ a(1)^2 + b(1) + c = 3 \quad \Rightarrow \quad a + b + c = 3 \] \[ a(2)^2 + b(2) + c = 7 \quad \Rightarrow \quad 4a + 2b + c = 7 \] \[ a(3)^2 + b(3) + c = 13 \quad \Rightarrow \quad 9a + 3b + c = 13 \] 4. **Solve the System:** Subtract the first equation from the second: \[ 3a + b = 4 \] Subtract the second equation from the third: \[ 5a + b = 6 \] Subtract these two new equations: \[ 2a = 2 \quad \Rightarrow \quad a = 1 \] Then: \[ 3(1) + b = 4 \quad \Rightarrow \quad b = 1 \] Finally: \[ 1 + 1 + c = 3 \quad \Rightarrow \quad c = 1 \] 5. **Final Formula:** \[ a_n = n^2 + n + 1 \] 6. **Calculate the \( 10^{\text{th}} \) Term:** \[ a_{10} = 10^2 + 10 + 1 = 100 + 10 + 1 = 111 \] **Please provide the initial terms of your sequence**, and I'd be happy to help you work out the \( n^{\text{th}} \) term and find the \( 10^{\text{th}} \) term specifically.

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The Deep Dive

To find the \( n^{\text{th}} \) term of a quadratic sequence, first, identify the difference between consecutive terms. Calculate the first difference and then the second difference. If the second difference is constant, you can determine the general form of the \( n^{\text{th}} \) term as \( an^2 + bn + c \). Once you establish \( a \), \( b \), and \( c \), you can substitute \( n = 10 \) into the formula to find the \( 10^{\text{th}} \) term! Once you have the formula for your sequence, plug in \( n = 10 \) and calculate \( a(10^2) + b(10) + c \) to get the final term. This simple substitution could lead to a thrilling discovery—just like unearthing the treasure hidden in a pirate's map!

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