Karabo and John are of the same rest stop alongside a highway. harobo started driving along the high way at a constant speed \( 80 \mathrm{~km} / \mathrm{h} \). An hour laler, Johnstarted driving along the same high way in the same direction as Karabo at a constant speed of \( 100 \mathrm{~km} / \mathrm{h} \). How long will it take John to catch up with Karabo?

Karabo has a one-hour head start, driving at 80 km/h. So, in that hour, he covers a distance of \( 80 \, \text{km} \) (since \( 80 \, \text{km/h} \times 1 \, \text{h} = 80 \, \text{km} \)). After John starts driving, he is going 20 km/h faster than Karabo (100 km/h - 80 km/h). To find out how long it will take John to close that 80 km gap, you can use the formula \( \text{time} = \frac{\text{distance}}{\text{speed}} \). So, it would be \( \frac{80 \, \text{km}}{20 \, \text{km/h}} = 4 \, \text{h} \). Therefore, it will take John 4 hours to catch up with Karabo after he starts driving. Isn’t it interesting how simple math can resolve real-life situations like this? This kind of problem often appears in physics or driving scenarios, helping to enhance your logical reasoning and analytical skills. Next time you’re on a road trip, try to calculate how long it will take to reach your destination based on your speed and any stops you may take!