Multiply, and then simplify if possible. \( (\sqrt{5}-\sqrt{2})^{2} \) \( (\sqrt{5}-\sqrt{2})^{2}=\square \) (Simplify your answer. Do not factor. Type an exact answer, using radicals as needed.)

To multiply \( (\sqrt{5}-\sqrt{2})^{2} \), we can use the formula for squaring a binomial: \( (a-b)^{2} = a^{2} - 2ab + b^{2} \). Here, \( a = \sqrt{5} \) and \( b = \sqrt{2} \). Calculating: 1. \( a^{2} = (\sqrt{5})^{2} = 5 \) 2. \( b^{2} = (\sqrt{2})^{2} = 2 \) 3. \( -2ab = -2(\sqrt{5})(\sqrt{2}) = -2\sqrt{10} \) Putting it all together, we have: \[ (\sqrt{5}-\sqrt{2})^{2} = 5 - 2\sqrt{10} + 2 \] Simplifying this, we get: \[ 5 + 2 = 7 \] Thus, the final expression is: \[ (\sqrt{5}-\sqrt{2})^{2} = 7 - 2\sqrt{10} \] So, the answer is: \( \sqrt{5}-\sqrt{2})^{2} = 7 - 2\sqrt{10} \)