24) \( 16 x y-56 x+2 y-7 \)

To factor the expression \( 16xy - 56x + 2y - 7 \), let's group the terms in pairs. We can rearrange it as follows: \[ (16xy - 56x) + (2y - 7) \] Now, for the first group \( 16xy - 56x \), we can factor out \( 8x \): \[ 8x(2y - 7) \] For the second group \( 2y - 7 \), we notice that it is already in a simplified form. Thus, we combine both groups: \[ 8x(2y - 7) + 1(2y - 7) \] Now, we can factor \( 2y - 7 \) out from both terms: \[ (2y - 7)(8x + 1) \] So, the fully factored form of the expression is: \[ (2y - 7)(8x + 1) \]