Question
The city of Raleigh has 11100 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 200 randomly selected registered voters was conducted. 115 said they'd vote for Brown, 66 said they'd vote for Feliz, and 19 were undecided. Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Note: Answer as a reduced fraction. This sample statistic suggests that we might expect to vote for Brown.
Ask by Parsons Reeves. in the United States
Mar 21,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The sample statistic for the proportion of voters who said they'd vote for Brown is \(\frac{23}{40}\). This suggests that we might expect \(\frac{23}{40}\) of the voters to vote for Brown.
Solution
The sample statistic for the proportion is given by
\[
\frac{115}{200}.
\]
To reduce, divide the numerator and denominator by their greatest common divisor, which is 5:
\[
\frac{115 \div 5}{200 \div 5} = \frac{23}{40}.
\]
Thus, the sample statistic is \(\frac{23}{40}\).
This suggests that we might expect \(\frac{23}{40}\) of the voters to vote for Brown.
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Simplify this solution Extra Insights
To find the sample statistic for the proportion of voters who said they'd vote for Brown, we take the number of voters who support Brown (115) and divide it by the total number of voters surveyed (200). So, the sample statistic is 115/200, which can be reduced to 23/40. This proportion suggests that if the same trends hold in the larger population, we might expect approximately 57.5% of the overall voters in Raleigh to support Brown! That's a noticeable lead, which could give him a strong advantage going into election day.
