For each of the following, write three fractions equal to the given fraction. \( \begin{array}{ll}\text { a. } \frac{1}{3} & \text { b. } \frac{6}{7} \\ \text { c. } \frac{-9}{10} & \text { d. } \frac{a}{8} \\ \frac{6}{7}=\frac{\square}{21} \\ \text { (Simplify your answer.) } \\ \text { Enter the correct numerator to match the new denominator. } \\ \frac{6}{7}=\frac{\square}{63} \text { (Simplify your answer.) } \\ \text { Enter the correct numerator to match the new denominator. } \\ \frac{6}{7}=\frac{\square}{42} \text { (Simplify your answer.) }\end{array} \)
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To generate fractions equivalent to the given ones, let's identify some using basic multiplication of the numerator and denominator. For \( \frac{1}{3} \): 1. \( \frac{2}{6} \) (multiply both numerator and denominator by 2) 2. \( \frac{3}{9} \) (multiply both by 3) 3. \( \frac{4}{12} \) (multiply both by 4) For \( \frac{6}{7} \): 1. To find \( \frac{6}{7}=\frac{\square}{21} \): Multiply both by 3. So, \( \frac{6 \times 3}{7 \times 3} = \frac{18}{21} \) (Fill in 18). 2. To find \( \frac{6}{7}=\frac{\square}{63} \): Multiply both by 9. So, \( \frac{6 \times 9}{7 \times 9} = \frac{54}{63} \) (Fill in 54). 3. To find \( \frac{6}{7}=\frac{\square}{42} \): Multiply both by 6. So, \( \frac{6 \times 6}{7 \times 6} = \frac{36}{42} \) (Fill in 36). For \( \frac{-9}{10} \): 1. \( \frac{-18}{20} \) (multiply both by 2) 2. \( \frac{-27}{30} \) (multiply both by 3) 3. \( \frac{-36}{40} \) (multiply both by 4) For \( \frac{a}{8} \), the equivalent fractions will depend on the value of \( a \): 1. \( \frac{2a}{16} \) (multiply both by 2) 2. \( \frac{3a}{24} \) (multiply both by 3) 3. \( \frac{4a}{32} \) (multiply both by 4)