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Home Question Bank Math Algebra Archive 2024 December 03

Algebra Questions from Dec 03,2024

Browse the Algebra Q&A Archive for Dec 03,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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A plumber charges a customer a one-time service fee of \( \$ 79, \$ 62 \) per hour for labor, and a surcharge of \( \$ 15 \) per hour doe to the call being an emergence White an expression to represent the total charges for the plumber two different ways. Let \( h \) represent the number of hours the job takes. Enter the correct answers in the boxes. a) \( \left\{\begin{array}{c}x+y+w=10 \\ 2 x-2 y+w=4 \\ 3 x-y+w=3\end{array}\right. \) Al resolver la Ecuación Exponencial \( 2^{(2 x+1)}=4 \), se obtiene: Factor: \( 2 a^{3}+10 a^{2}+12 a \) Factor: \( 375 a m^{3}-24 a n^{3} \) 4. \( \left(2 x^{3}-\frac{1}{2 x}\right)^{2}-2 x\left(4 x^{4}+3\right)= \) Factor: \( 81 c^{2}-4 w^{2} \) 13 When solving a problem, it's important to use the right tool for the job. How would you solve this A local theater group is putting on a performance. It costs \( \$ 500 \) per night to rent the theater spa tickets for adults at \( \$ 5.00 \) and tickets for students at \( \$ 2.50 \). If the group sold only the higher pric Let \( x= \) people attending the performance Cost \( =\$ 500+\$ 0.75 x \) Revenue \( =\$ 5.00 x \) A. make a graph and see where the lines representing cost and revenue cross B. make a graph and plug in values C. set cost equal to revenue and use algebra to solve for \( x \) Algebra 1 P.5 Write two-variable inequalities: word problems ZAY Tori is selling handmade jewelry to earn money for camp. Bracelets sell for \( \$ 8 \) and necklaces sell for \( \$ 24 \), and she needs to make at least \( \$ 300 \) in revenue to cover the cost of camp. Select the inequality in standard form that describes this situation. Use the given numbers and the following variables. \( x= \) the number of bracelets \( y= \) the number of necklaces QUESTION 7 - 1 POINT Factor \( 14 y^{2}+31 y+15 \)
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