Write the expression as a single logarithm. \[ 2 \log _{6}(x+8)-\log _{6}(x-6)-\log _{6}(x-12) \] \( 2 \log _{6}(x+8)-\log _{6}(x-6)-\log _{6}(x-12)=\square \) \( ( \) Simplify your answer.)

Solve the absolute value inequality. \( |x-6| \geq 1 \) A. The solution set in interval notation is (Simplify your answer.) B. The solution set is \( \varnothing \).

5. Fourth term of arith sequence is 11 , and the \( 6^{2} \) term is 17 . Find the second term. \( a_{4}=11 \quad a_{6}=17 \quad a_{1}+(n-1) \)

\[ 11^{-x-4}=4^{3 x} \] Write the exact answer using either base-10 or base-e logarithms. \( x=\square \)

Let \( A=\left[\begin{array}{cc}4 & 5 \\ 1 & -5\end{array}\right] \) and \( B=\left[\begin{array}{cc}2 & -6 \\ 2 & 3\end{array}\right] \) Find \( -2 A+5 B \) \( -2 A+5 B= \)

7. \( \begin{aligned} y & =2 x+8 \\ y & =-2 x\end{aligned} \)