9. The solutions to \( 3 x^{2}-8 x+4=-1 \) are \( \begin{array}{ll}\text { a. } 1,5 / 3 & \text { b. }-1,-5 / 3 \\ \text { c. } 5,1 / 3 & \text { d. }-5,-1 / 3\end{array} \)

5. Fourth term of arith sequence is 11 , and the \( 6^{2} \) term is 17 . Find the second term. \( a_{4}=11 \quad a_{6}=17 \quad a_{1}+(n-1) \)

Solve the absolute value inequality. \( |x-6| \geq 1 \) A. The solution set in interval notation is (Simplify your answer.) B. The solution set is \( \varnothing \).

10. \( \begin{array}{l}x+y=3 \\ 2 x+4 y=8\end{array} \)

lify \( \left(\frac{x^{-2} y^{-1 / 3}}{x^{-5 / 3} y^{-2 / 3}}\right)^{3} \) so there

\[ \begin{array}{l}|x+6| \leq 7\end{array} \] Solve the absolute value inequality. A. The solution set in interval notation is (Simplify your answer.) The solution set is \( \varnothing \).