15. Hasil dari \( \left(\mathrm{a}^{3} \mathrm{~b}^{-2}\right)\left(\mathrm{a}^{-2} \mathrm{~b}^{3}\right)^{-3} \) adalah .... A. \( \left(a b^{\prime 9}\right. \) B. \( \left(\frac{a}{b}\right)^{1} \) C. \( (a b)^{11} \) D. \( \left(\frac{a}{b}\right)^{11} \) E. \( \frac{a^{\prime}}{b^{11}} \)

7. \( a, b \) ve \( c \) gerçel sayıları için \( a>0>b \cdot a \) \( b>c \) olduğuna göre, aşağıdakilerden hangisi kesinlil pozitiftir? \( \begin{array}{lll}\text { A) } a \cdot c & \text { B) } a \cdot b \cdot c & \text { C) } c \\ \text { D) } a+c & \text { E) } b^{2} \cdot c\end{array} \)

268. Решите уравнение: \( \begin{array}{l}\text { a) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \\ \text { (B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; } \\ \text { (A) }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \)

268. Решите уравнение: \( \begin{array}{l}\text { а) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \text {; } \\ \text { B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \).

Evaluate the following function. Your answer should be an integer. \( f(x)=-3^{2 x-2} \), for \( x=3 \) Your answer is \( f(3)=\square \)

1.1.1 \( x=\frac{4}{x}+3 \)