A car was valued at \( \$ 34,000 \) in the year 1990 . The value depreciated to \( \$ 11,000 \) by the year 2006 . A) What was the annual rate of change between 1990 and 2006 ? \( r=\square \) Round the rate of decrease to 4 decimal places.

\( \$ 5000 \) are invested in a bank account at an interest rate of 5 percent per year. Find the amount in the bank after 13 years if interest is compounded annually. Find the amount in the bank after 13 years if interest is compounded quarterly. Find the amount in the bank after 13 years if interest is compounded monthly. Finally, find the amount in the bank after 13 years if interest is compounded continuously.

Find the time required for an investment of 5000 dollars to grow to 6500 dollars at an interest rate of 7.5 percent per year, compounded quarterly. Your answer is \( t=\square \) years. You may enter the exact value or round to 2 decimal places.

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We deposit \( \$ 17000 \) into an account earning \( 4 \% \) interest compounded semiannually. How many years will it take for the account to grow to \( \$ 42500 \) ? Round to 2 decimal places. \( \square \) years

A car was valued at \( \$ 31,000 \) in the year 1991 . The value depreciated to \( \$ 13,000 \) by the year 2007 . A) What was the annual rate of change between 1991 and 2007? \( r=\square \) Round the rate of decrease to 4 decimal places. B) What is the correct answer to part A written in percentage form? \( r=\square \). C) Assume that the car value continues to drop by the same percentage. What will the value be in the year 2010 ? value \( =\$ \square \) Round to the nearest 50 dollars.