Give exact and approximate solutions. \( 3 x^{2}-5 x-7=0 \) The exact solutions are \( x=\square \). (Simplify your answer, including any radicals and \( i \) as needed. Use integers or fractions for any numbers in the expression. Use answers as needed.) The approximate solutions are \( x=\square \). (Use a comma to separate answers as needed. Round to the nearest thousandth as needed.)

\[ 11^{-x-4}=4^{3 x} \] Write the exact answer using either base-10 or base-e logarithms. \( x=\square \)

lify \( \left(\frac{x^{-2} y^{-1 / 3}}{x^{-5 / 3} y^{-2 / 3}}\right)^{3} \) so there

5. Fourth term of arith sequence is 11 , and the \( 6^{2} \) term is 17 . Find the second term. \( a_{4}=11 \quad a_{6}=17 \quad a_{1}+(n-1) \)

Solve the absolute value inequality. \( |x-6| \geq 1 \) A. The solution set in interval notation is (Simplify your answer.) B. The solution set is \( \varnothing \).

Given \( f(x)=-3 x+4 \) and \( g(x)=x+7 \), what is the value of \( g(f(2)) ? \)