A pipe opened at both ends resonates at a fundamental frequency, \( f_{e} \). When one end is closed, the pipe resonates at a fundamental frequency \( f_{c} \). The relationship between \( f_{0} \) and \( f_{e} \) is A. \( f_{0}=2 f_{c} \) B. \( 2 f_{0}=f_{c} \) C. \( 3 f_{0}=2 f_{c} \) D. \( f_{0}=f_{c} \)

Fizika(8007242) 5 kV ga teng. Unga ta'sir qilayotgan natijaviy kuchni ( kN\( ) \) toping. A) 5 B) 3 C) 8 D) 13

Use the formula \( s=r \omega t \) to find the value of the missing variable. \( s=\frac{4 \pi}{5} \mathrm{~km}, r=5 \mathrm{~km}, t=1 \mathrm{sec} \)

Exercice 5 : Déflexion Une particule chargée pénètre \( \vec{E}=E \overrightarrow{e_{y}} \). 1. Trouver les composantes dy 2. En déduire les composante 3. Trouver l'angle \( \theta \) qui repré 4. Trouver le temps requis po

Bandgap and photodetection (a) Determine the maximum value of the energy gap which a semiconductor, used as a photoconductor, can have if it is to be sensitive to yellow light ( 600 nm ). (b) A photodetector whose area is \( 5 \times 10^{-2} \mathrm{~cm}^{2} \) is irradiated with yellow light whose intensity is \( 20 \mathrm{~mW} \mathrm{~cm}^{-2} \). Assuming that each photon generates one electron-hole pair, calculate the number of pairs generated per second.

Exercice 5 : Déflexio Une particule chargée pénètre \( \vec{E}=E \overrightarrow{e_{y}} \). 1. Trouver les composantes c 2. En déduire les composant 3. Trouver l'angle \( \theta \) qui repr 4. Trouver le temps requis \( p \)