Quincy is going on vacation and taking his dog Pickles along. Pickles eats 3 cups of Hungry Hound dog food each day. Quincy wants to know how many days he can feed Pickles from a 15 -cup bag of Hungry Hound. Which equation can Quincy use to find the number of days \( d \) he can feed Pickles from the bag. \( 3 d=15 \) Solve this equation for \( d \) to find the number of days Quincy can feed Pickles. days

268. Решите уравнение: \( \begin{array}{l}\text { a) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \\ \text { (B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; } \\ \text { (A) }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \)

268. Решите уравнение: \( \begin{array}{l}\text { а) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \text {; } \\ \text { (B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; } \\ \text { (A) }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \)

\( \log _ { 2 } ^ { 2 } x - 15 \log _ { 5 } x - 4 \leq 0 \)

\( \sqrt { n ^ { 2 } - 1 } - ( n + 1 ) = \frac { ( n ^ { 2 } - 1 ) - ( n + 1 ) ^ { 2 } } { \sqrt { n ^ { 2 } - 1 } + ( n + 1 ) } = \frac { - 2 n - 2 } { \sqrt { n ^ { 2 } - 1 } + ( n + 1 ) } \rightarrow - 1 \)

1.1.1 \( x=\frac{4}{x}+3 \)