1.3. Simplify the following without the aid of a calculat 1.3.1. \( \left(3,6 \times 10^{6}\right)-\left(5,2 \times 10^{5}\right) \) 1.3.2. \( \frac{1}{2}+2 \frac{3}{4}-\frac{3}{8} \) 1.3.3. \( \sqrt{\sqrt{(16)^{2}}}-\frac{3}{4} \) 1.3.4. \( \left(7^{-2}+7^{-1}\right) \div(21 \div 3) \)
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To tackle the first problem, \( \left(3.6 \times 10^{6}\right)-\left(5.2 \times 10^{5}\right) \), we need to express both numbers in compatible powers of ten. Converting \( 5.2 \times 10^{5} \) to the same power as \( 3.6 \times 10^{6} \) gives us \( 0.52 \times 10^{6} \). Now, we can easily subtract: \( 3.6 - 0.52 = 3.08 \). Thus, the final answer is \( 3.08 \times 10^{6} \). For the second, let's simplify \( \frac{1}{2}+2 \frac{3}{4}-\frac{3}{8} \). First, convert \( 2 \frac{3}{4} \) to an improper fraction: that’s \( \frac{11}{4} \). Finding a common denominator of 8, we rewrite everything as: \( \frac{4}{8} + \frac{22}{8} - \frac{3}{8} = \frac{4 + 22 - 3}{8} = \frac{23}{8} \) or as a mixed number, \( 2 \frac{7}{8} \). For \( \sqrt{\sqrt{(16)^{2}}}-\frac{3}{4} \), calculate \( (16)^{2} = 256 \). The square root of 256 is 16, and taking the square root again gives us 4. So the expression simplifies to: \( 4 - \frac{3}{4} \). Convert 4 to \( \frac{16}{4} \): \( \frac{16}{4} - \frac{3}{4} = \frac{13}{4} \) or \( 3 \frac{1}{4} \) in mixed form. Last but not least, \( \left(7^{-2}+7^{-1}\right) \div(21 \div 3) \). First, simplify \( 21 \div 3 = 7 \). Calculating \( 7^{-2} = \frac{1}{49} \) and \( 7^{-1} = \frac{1}{7} \). Find a common denominator for the addition: Using \( 49 \): \( \frac{1}{49} + \frac{7}{49} = \frac{8}{49} \). Now divide by 7: \(\frac{8}{49} \div 7 = \frac{8}{343}\). These brain teasers are both fun and a great exercise for sharpening math skills!