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Question 5 - Add and Subtract Polynomials COLLEGE LIVING The total number of students \( T \) who attend a college consists of two groups: students who live in dorm rooms on campus \( D \) and students who live in apartments off campus \( A \). The number (in hundreds) of students who live in dorm rooms and the total number of students enrolled in the college can be modeled by the following equations, where \( n \) is the number of years since 2001. \[ \begin{array}{l} T=17 n+23 \\ D=11 n+8 \end{array} \] Part A Write an equation that models the number of students who live in apartments. Part B Predict the number of students who will live in apartments in 2020. Part C What do you need to assume in order to predict the number of students who will live on campus in 2020? A. The total number of students does not include students who commute. B. Students do not share dorm rooms. C. The number of students enrolled in the college remains the same. D. Many students live at home during the summer. Question 6 - Solve Equations with Polynomial Expressions Solve each equation. a. \( 2 p=3(4 p-10) \) b. \( -3 q(2 q+5)=2\left(-3 q^{2}+15\right)-5(10 q+6) \)

Ask by Stephens Todd. in the United States
Feb 20,2025

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**Question 5:** - **Part A:** The number of students who live in apartments is modeled by \( A = 6n + 15 \). - **Part B:** In 2020, approximately 12,900 students will live in apartments. - **Part C:** To predict the number of students living on campus in 2020, we assume that the total number of students enrolled in the college remains the same. **Question 6:** - **Part a:** The solution to \( 2p = 3(4p - 10) \) is \( p = 3 \). - **Part b:** The solution to \( -3q(2q + 5) = 2(-3q^2 + 15) - 5(10q + 6) \) is \( q = 0 \).

Solution

Let's solve the problems step by step. ### Question 5 - Add and Subtract Polynomials #### Part A: Write an equation that models the number of students who live in apartments. We know that the total number of students \( T \) is the sum of students living in dorms \( D \) and those living in apartments \( A \). This can be expressed as: \[ T = D + A \] Substituting the given equations for \( T \) and \( D \): \[ 17n + 23 = (11n + 8) + A \] To find \( A \), we rearrange the equation: \[ A = T - D = (17n + 23) - (11n + 8) \] Now, simplifying this: \[ A = 17n + 23 - 11n - 8 = 6n + 15 \] Thus, the equation that models the number of students who live in apartments is: \[ A = 6n + 15 \] #### Part B: Predict the number of students who will live in apartments in 2020. To find the number of years since 2001 for the year 2020, we calculate: \[ n = 2020 - 2001 = 19 \] Now, substituting \( n = 19 \) into the equation for \( A \): \[ A = 6(19) + 15 \] Calculating this: \[ A = 114 + 15 = 129 \] Since \( A \) is in hundreds, the predicted number of students who will live in apartments in 2020 is: \[ 129 \times 100 = 12900 \] #### Part C: What do you need to assume in order to predict the number of students who will live on campus in 2020? The correct assumption is: **C. The number of students enrolled in the college remains the same.** ### Question 6 - Solve Equations with Polynomial Expressions #### Part a: Solve \( 2p = 3(4p - 10) \) First, distribute on the right side: \[ 2p = 12p - 30 \] Now, rearranging the equation to isolate \( p \): \[ 2p - 12p = -30 \] This simplifies to: \[ -10p = -30 \] Dividing both sides by -10: \[ p = 3 \] #### Part b: Solve \( -3q(2q + 5) = 2(-3q^2 + 15) - 5(10q + 6) \) First, simplify both sides. Starting with the left side: \[ -3q(2q + 5) = -6q^2 - 15q \] Now, simplifying the right side: \[ 2(-3q^2 + 15) = -6q^2 + 30 \] \[ -5(10q + 6) = -50q - 30 \] Combining these: \[ -6q^2 + 30 - 50q - 30 = -6q^2 - 50q \] Now, we have: \[ -6q^2 - 15q = -6q^2 - 50q \] Adding \( 6q^2 \) to both sides: \[ -15q = -50q \] Now, adding \( 50q \) to both sides: \[ 35q = 0 \] Dividing by 35: \[ q = 0 \] ### Summary of Answers: - Part A: \( A = 6n + 15 \) - Part B: 12900 students in apartments in 2020. - Part C: C. The number of students enrolled in the college remains the same. - Part a: \( p = 3 \) - Part b: \( q = 0 \)

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To find the number of students living in apartments, we can use the given equations for \( T \) and \( D \): \( A = T - D \). Plugging in the values, we find that \( A = (17n + 23) - (11n + 8) = 6n + 15 \). This means the number of students living in apartments can be modeled by the equation \( A = 6n + 15 \). To predict the number of students living in apartments in 2020, we need to find the value of \( n \) for that year. Since \( n \) represents the number of years since 2001, for 2020, \( n = 19 \). Plugging that into the equation \( A = 6(19) + 15 \) gives us \( A = 114 + 15 = 129 \). Therefore, by 2020, there will be approximately 1,290 students living in apartments! To predict the number of students living on campus in 2020, we need to ensure that the total enrollment does not fluctuate dramatically from existing trends. The most sensible assumption is C: The number of students enrolled in the college remains the same. This ensures our predictions align with established growth patterns observed in the previous years. --- The trend of college students living in various accommodations began to shift significantly around the 1960s. As campuses expanded, more students began opting for the experience of campus life, leading to an increase in on-campus housing and, subsequently, a rise in dorm population. Understanding this historical perspective helps us anticipate future trends in student accommodations. Calculating with polynomials often brings up the age-old challenge of mismanagement in distribution—common mistakes include forgetting to distribute correctly or combining like terms prematurely. A nifty tip is to always double-check your signs and terms before wrapping it up, ensuring you don't miss a crucial negative sign! A systematic approach can keep your calculations as smooth as butter!

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