Solve for \( x \). Enter the solutions from least to greatest. \( 6 x^{2}-12 x-210=0 \) lesser \( x=\square \) greater \( x= \)

To solve the quadratic equation \( 6 x^{2}-12 x-210=0 \), we first simplify by dividing the entire equation by 6: \[ x^{2} - 2x - 35 = 0 \] Next, we factor the quadratic: \[ (x - 7)(x + 5) = 0 \] Setting each factor to zero gives us the solutions: \[ x - 7 = 0 \quad \Rightarrow \quad x = 7 \] \[ x + 5 = 0 \quad \Rightarrow \quad x = -5 \] Thus, the solutions are: lesser \( x = -5 \) greater \( x = 7 \)