Question
upstudy study bank question image url

\( (3+\sqrt{5}) \) and \( (3-\sqrt{5}) \)

Ask by Curry Medina. in Nigeria
Jan 11,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are conjugate expressions with a sum of 6 and a product of 4. They are roots of the quadratic equation \( x^2 - 6x + 4 = 0 \).

Solution

It looks like you're working with the expressions \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \). These two expressions are **conjugates** of each other. Conjugate pairs like these have several interesting properties, especially in the context of algebra and quadratic equations. Here's a breakdown of their key properties and how they relate to each other: ### 1. **Sum and Product** - **Sum:** \[ (3 + \sqrt{5}) + (3 - \sqrt{5}) = 3 + \sqrt{5} + 3 - \sqrt{5} = 6 \] - **Product:** \[ (3 + \sqrt{5})(3 - \sqrt{5}) = 3^2 - (\sqrt{5})^2 = 9 - 5 = 4 \] These results are derived from the algebraic identity for the product of conjugates: \[ (a + b)(a - b) = a^2 - b^2 \] ### 2. **Quadratic Equation** Since \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are roots of a quadratic equation, you can construct that equation using their sum and product. For a quadratic equation of the form: \[ x^2 - ( \text{sum of roots} )x + ( \text{product of roots} ) = 0 \] Plugging in the sum and product: \[ x^2 - 6x + 4 = 0 \] So, the quadratic equation with roots \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) is: \[ x^2 - 6x + 4 = 0 \] ### 3. **Other Properties** - **Irrationality:** Both \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are irrational numbers because they involve the square root of a non-square integer (5). - **Reciprocals:** \[ \frac{1}{3 + \sqrt{5}} = \frac{3 - \sqrt{5}}{(3 + \sqrt{5})(3 - \sqrt{5})} = \frac{3 - \sqrt{5}}{4} \] Similarly, \[ \frac{1}{3 - \sqrt{5}} = \frac{3 + \sqrt{5}}{4} \] - **Powers:** Raising these expressions to higher powers can be simplified using their quadratic relationship. For example: - **Square:** \[ (3 + \sqrt{5})^2 = 9 + 6\sqrt{5} + 5 = 14 + 6\sqrt{5} \] \[ (3 - \sqrt{5})^2 = 9 - 6\sqrt{5} + 5 = 14 - 6\sqrt{5} \] - **Recurrence Relations:** Due to their role as roots of a quadratic equation, sequences involving these terms can often be expressed using linear recurrence relations. ### 4. **Applications** Conjugate pairs like \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) frequently appear in various areas of mathematics, including: - **Solving Quadratic Equations:** As shown, they serve as solutions to specific quadratic equations. - **Number Theory:** They can be involved in problems related to algebraic integers. - **Geometry:** Expressions involving square roots are common in geometric calculations, such as distance formulas. - **Continued Fractions:** Conjugate irrationals can be used to study properties of continued fractions. ### 5. **Graphical Representation** If you were to plot these as points on the real number line: - Both points are located at a distance of \( \sqrt{5} \) from the point 3. - \( (3 + \sqrt{5}) \) is to the right of 3, while \( (3 - \sqrt{5}) \) is to the left. ### Summary - **Conjugates:** \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are a pair of conjugate expressions. - **Sum:** 6 - **Product:** 4 - **Quadratic Equation:** \( x^2 - 6x + 4 = 0 \) - **Properties:** Irrational, have reciprocal relationships, and can be manipulated using algebraic identities. If you have a specific question or need further elaboration on a particular aspect of these expressions, feel free to ask!

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Beyond the Answer

Did you know that the expressions \( (3+\sqrt{5}) \) and \( (3-\sqrt{5}) \) are actually conjugates? Their unique connection helps in simplifying many mathematical problems, especially when working with quadratic equations or in rationalizing denominators! When you multiply them together, you get a difference of squares resulting in \( (3+\sqrt{5})(3-\sqrt{5}) = 9 - 5 = 4 \). Magic, isn’t it? Now, let’s think about how these expressions can come in handy in the real world! For instance, they might be used in computations related to geometry when you're dealing with the lengths of sides in certain types of triangles. If one of your triangle's dimensions is expressed as \( 3 \pm \sqrt{5} \), you can easily calculate the relative proportions or even areas using these delightful numbers. Numbers have personality too!

Related Questions

Latest Algebra Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy