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Elimantion tnethod \( 2 x-y=-1 \times 1 \) \( x-2 y=4 \times 2 \) \( -2 x-y=-1 \) \( 2 x-4 y=8 \) \( -y--4 y=-1-8 \) \( -y+4 y-9 \) \( y=-3 \)

Ask by King Johnston. in Nigeria
Jan 11,2025

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Answer

The solution is \( x = -2 \) and \( y = -3 \).

Solution

It looks like you're working through a system of linear equations using the **elimination method**. Let's carefully go through each step to ensure accuracy and clarity. ### Given System of Equations: \[ \begin{cases} 2x - y = -1 \quad \text{(Equation 1)} \\ x - 2y = 4 \quad \text{(Equation 2)} \end{cases} \] ### Goal: Solve for the variables \( x \) and \( y \) by eliminating one of the variables. ### Step 1: Align the Equations for Elimination To eliminate one of the variables, we'll manipulate the equations so that adding or subtracting them cancels out one variable. #### Option 1: Eliminate \( x \) 1. **Multiply Equation 2 by 2** to make the coefficients of \( x \) in both equations equal (but opposite in sign). \[ \begin{align*} \text{Equation 1:} \quad 2x - y &= -1 \quad \times 1 \\ \text{Equation 2:} \quad x - 2y &= 4 \quad \times 2 \\ \end{align*} \] This yields: \[ \begin{align*} 2x - y &= -1 \quad \text{(Equation 1)} \\ 2x - 4y &= 8 \quad \text{(Equation 2 Modified)} \end{align*} \] 2. **Subtract Equation 1 from the modified Equation 2** to eliminate \( x \): \[ \begin{align*} (2x - 4y) - (2x - y) &= 8 - (-1) \\ 2x - 4y - 2x + y &= 9 \\ -3y &= 9 \\ y &= \frac{9}{-3} \\ y &= -3 \end{align*} \] ### Step 2: Solve for \( x \) Now that we have \( y = -3 \), substitute this value back into one of the original equations to find \( x \). Let's use **Equation 1**: \[ 2x - y = -1 \] Substitute \( y = -3 \): \[ 2x - (-3) = -1 \\ 2x + 3 = -1 \\ 2x = -1 - 3 \\ 2x = -4 \\ x = \frac{-4}{2} \\ x = -2 \] ### Step 3: Write the Solution The solution to the system of equations is: \[ x = -2 \\ y = -3 \] ### Verification It's always good practice to verify the solution by plugging the values back into both original equations. 1. **Equation 1:** \[ 2(-2) - (-3) = -4 + 3 = -1 \quad \checkmark \] 2. **Equation 2:** \[ (-2) - 2(-3) = -2 + 6 = 4 \quad \checkmark \] Both equations are satisfied, so the solution is correct. ### Summary Using the elimination method: 1. **Aligned the equations** to eliminate \( x \). 2. **Subtracted** the equations to solve for \( y \). 3. **Substituted** the value of \( y \) back into one of the original equations to find \( x \). 4. **Verified** the solution by plugging the values back into the original equations. The final solution is \( x = -2 \) and \( y = -3 \).

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The elimination method is a powerful technique for solving systems of linear equations. It involves eliminating one variable by combining equations, allowing you to solve for the remaining variable. In your example, you correctly manipulated the equations to isolate \(y\). Once \(y\) is found, you substitute it back into one of the original equations to find \(x\). A common mistake when using the elimination method is to miscalculate when combining equations. It's crucial to keep track of signs and coefficients! For example, watch out for sign errors like the switch from \( -y + 4y \) to \( -y - 4y \). Double-checking arithmetic and maintaining systematic setup helps ensure accuracy—after all, math should be fun, not frustrating!

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