Evaluate the following equation for $$ x=3 $$ $$ y=4(x-2)+7 $$ (1 point) $$ y=\square $$

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Evaluate the expression by following steps:
- step0: Evaluate:
  $$4\left(x-2\right)+7$$
- step1: Substitute:
  $$4\left(3-2\right)+7$$
- step2: Subtract the numbers:
  $$4\times 1+7$$
- step3: Multiply:
  $$4+7$$
- step4: Add the numbers:
  $$11$$
To evaluate the equation $$ y = 4(x-2) + 7 $$ for $$ x = 3 $$:

1. Substitute $$ x = 3 $$ into the equation:
   $$
   y = 4(3-2) + 7
   $$

2. Calculate the expression:
   $$
   y = 4(1) + 7 = 4 + 7 = 11
   $$

Thus, the value of $$ y $$ is $$ 11 $$.

So, $$ y = 11 $$.
$$ y = 11 $$

Evaluate the following equation for
(1 point)

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