a. $$ 6 \cdot \sqrt{3}-\frac{2}{3} \cdot \sqrt{243}+\frac{8}{3} \cdot \sqrt{27} $$

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Calculate or simplify the expression $$ 6 \cdot \sqrt{3}-\frac{2}{3} \cdot \sqrt{243}+\frac{8}{3} \cdot \sqrt{27} $$.
Calculate the value by following steps:
- step0: Calculate:
  $$6\sqrt{3}-\frac{2}{3}\sqrt{243}+\frac{8}{3}\sqrt{27}$$
- step1: Simplify the root:
  $$6\sqrt{3}-\frac{2}{3}	imes 9\sqrt{3}+\frac{8}{3}\sqrt{27}$$
- step2: Simplify the root:
  $$6\sqrt{3}-\frac{2}{3}	imes 9\sqrt{3}+\frac{8}{3}	imes 3\sqrt{3}$$
- step3: Multiply the numbers:
  $$6\sqrt{3}-6\sqrt{3}+\frac{8}{3}	imes 3\sqrt{3}$$
- step4: Reduce the numbers:
  $$6\sqrt{3}-6\sqrt{3}+8\sqrt{3}$$
- step5: Simplify:
  $$8\sqrt{3}$$
La expresión $$6 \cdot \sqrt{3}-\frac{2}{3} \cdot \sqrt{243}+\frac{8}{3} \cdot \sqrt{27}$$ se simplifica a $$8\sqrt{3}$$.
La expresión simplifica a $$8\sqrt{3}$$.

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