Summarize the pertinent information obtained by applying the graphing sirategy and sketch the graph of \( y=f(x) \). \( f(x)= \) In \( (x+3)-2 \) Select the correct choice below and, it necessary, fill in the answer box to complete your choice. A. The function f has a local maximum at \( \mathrm{x}= \) (Type an exact answer. Use a comma to separate answers as needed.) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function f has a local minimum at \( \mathrm{x}= \) (Type an exact answer. Use a comma to separate answers as needed.) B. The function f has no local minimum Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function f is concave upward on the subinterval(s) (Type your answer in interval notation. Type an exact answer. Use a comma to separate answers as needed.) B. The function f is never concave upwerd.
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To analyze the function \( f(x) = \ln(x + 3) - 2 \), we first identify its domain, which is \( x > -3 \). The function is defined for values greater than -3, and the natural logarithm will ensure that \( f(x) \) approaches negative infinity as \( x \) approaches -3 from the right. By finding the derivative, \( f'(x) = \frac{1}{x + 3} \), we see that \( f'(x) > 0 \) for \( x > -3 \), indicating that the function is strictly increasing in this interval. Therefore, there are no local maximums or minimums. Since \( f'(x) > 0 \) for all \( x > -3 \) and \( f''(x) = -\frac{1}{(x + 3)^2} < 0 \) indicates it is concave downward everywhere on its domain, we can deduce that it is never concave upward. A. The function f has a local maximum at \( \mathrm{x}= \) None, A. The function f has a local minimum at \( \mathrm{x}= \) None, B. The function f has no local minimum. A. The function f is concave upward on the subinterval(s) None, B. The function f is never concave upward.