Question
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Given the following functions: \[ g(x)=x+2 \quad f(x)=x^{2}-5 \] Find the following: 1. \( g(-2)= \) 2. \( g(0)= \) 3. \( f(-2)= \) 4. \( f(0)= \) 5. The range of \( g \) when the domain is -1 .

Ask by Martin Rodriquez. in the United States
Mar 11,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

1. \( g(-2) = 0 \) 2. \( g(0) = 2 \) 3. \( f(-2) = -1 \) 4. \( f(0) = -5 \) 5. The range of \( g \) when the domain is \(-1\) is \(\{1\}\).

Solution

1. To find \( g(-2) \), substitute \(-2\) into \( g(x)=x+2 \): \[ g(-2)= -2+2 = 0. \] 2. To find \( g(0) \), substitute \(0\) into \( g(x)=x+2 \): \[ g(0)= 0+2 = 2. \] 3. To find \( f(-2) \), substitute \(-2\) into \( f(x)=x^{2}-5 \): \[ f(-2)= (-2)^2-5 = 4-5 = -1. \] 4. To find \( f(0) \), substitute \(0\) into \( f(x)=x^{2}-5 \): \[ f(0)= 0^2-5 = -5. \] 5. For the function \( g(x)=x+2 \) with the domain restricted to \(\{-1\}\) (i.e. the only allowed input is \( x=-1 \)), compute: \[ g(-1)= -1+2 = 1. \] Thus, the range is the set containing only \(1\), written as: \[ \{1\}. \]

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The Deep Dive

1. \( g(-2) = -2 + 2 = 0 \) 2. \( g(0) = 0 + 2 = 2 \) 3. \( f(-2) = (-2)^2 - 5 = 4 - 5 = -1 \) 4. \( f(0) = 0^2 - 5 = 0 - 5 = -5 \) 5. The range of \( g \) when the domain is -1 is simply the value at that point: \( g(-1) = -1 + 2 = 1 \); therefore, the range is {1}.

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