Given the following functions: $$ g(x)=x+2 \quad f(x)=x^{2}-5 $$ Find the following: 1. $$ g(-2)= $$ 2. $$ g(0)= $$ 3. $$ f(-2)= $$ 4. $$ f(0)= $$ 5. The range of $$ g $$ when the domain is -1 .

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1. To find $$ g(-2) $$, substitute $$-2$$ into $$ g(x)=x+2 $$:
   $$
   g(-2)= -2+2 = 0.
   $$

2. To find $$ g(0) $$, substitute $$0$$ into $$ g(x)=x+2 $$:
   $$
   g(0)= 0+2 = 2.
   $$

3. To find $$ f(-2) $$, substitute $$-2$$ into $$ f(x)=x^{2}-5 $$:
   $$
   f(-2)= (-2)^2-5 = 4-5 = -1.
   $$

4. To find $$ f(0) $$, substitute $$0$$ into $$ f(x)=x^{2}-5 $$:
   $$
   f(0)= 0^2-5 = -5.
   $$

5. For the function $$ g(x)=x+2 $$ with the domain restricted to $$\{-1\}$$ (i.e. the only allowed input is $$ x=-1 $$), compute:
   $$
   g(-1)= -1+2 = 1.
   $$
   Thus, the range is the set containing only $$1$$, written as:
   $$
   \{1\}.
   $$
1. $$ g(-2) = 0 $$ 2. $$ g(0) = 2 $$ 3. $$ f(-2) = -1 $$ 4. $$ f(0) = -5 $$ 5. The range of $$ g $$ when the domain is $$-1$$ is $$\{1\}$$.

Given the following functions: \[ g(x)=x+2 \quad f(x)=x^{2}-5 \] Find the following: 1. \( g(-2)= \) 2. \( g(0)= \) 3. \( f(-2)= \) 4. \( f(0)= \) 5. The range of \( g \) when the domain is -1 .

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