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Small Business Owners Seventy-six percent of small business owners do not have a college degree. If a random sample of 50 small business owners is selected, find the probability that exactly 41 will not have a college degree. Round the final answer to at least 4 decimal places and intermediate \( z \)-value calculations to 2 decimal places. \( P(X=41)= \)

Ask by Cook Davies. in the United States
Mar 11,2025

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Tutor-Verified Answer

Answer

The probability that exactly 41 out of 50 small business owners do not have a college degree is approximately 0.0851.

Solution

We are given that 76% of small business owners do not have a college degree. Let \( X \) be the number of owners in a sample of 50 without a college degree. Then \[ X \sim \text{Binomial}(n=50,\ p=0.76). \] We need to find the probability that exactly 41 do not have a degree, i.e., \[ P(X=41)= \binom{50}{41}(0.76)^{41}(0.24)^{50-41}. \] Using symmetry of the binomial coefficient, note that \[ \binom{50}{41} = \binom{50}{9}. \] Thus, \[ P(X=41)= \binom{50}{41}(0.76)^{41}(0.24)^9. \] To compute this probability: 1. **Binomial Coefficient:** \[ \binom{50}{41} = \binom{50}{9} = \frac{50!}{9!(50-9)!}. \] 2. **Probability term:** \[ (0.76)^{41}(0.24)^9. \] Combining these, \[ P(X=41)= \binom{50}{41}(0.76)^{41}(0.24)^9. \] Using a calculator or software to evaluate the above expression yields approximately \[ P(X=41) \approx 0.0851. \] Thus, \[ P(X=41) \approx 0.0851. \]

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To find the probability that exactly 41 out of 50 small business owners do not have a college degree, we can use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( n \) is the number of trials (50), \( k \) is the number of successful trials (41), and \( p \) is the probability of success (0.76). Using this, we first calculate \( \binom{50}{41} \): \[ \binom{50}{41} = \frac{50!}{41!(50-41)!} = \frac{50!}{41!9!} \] Now, we plug in the values: \[ P(X = 41) = \binom{50}{41} (0.76)^{41} (0.24)^{9} \] Calculating these values: 1. \( \binom{50}{41} \) can be computed or looked up to be approximately 0.0811. 2. \( (0.76)^{41} \) is approximately 0.0001. 3. \( (0.24)^{9} \) is approximately 0.000009. Now all together: \[ P(X = 41) \approx 0.0811 \times 0.0001 \times 0.000009 \approx 0.00007299 \] Thus, \( P(X=41) \approx 0.0001 \) rounded to four decimal places. Final answer: \( P(X=41) \approx 0.0001 \)

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