What is the \( x \)-value in the solution to this system of linear equations? \( \begin{array}{l}2 x-y=11 \\ x+3 y=-5 \\ -3 \\ -1 \\ 2 \\ 4\end{array} \)

Solve the system of equations \( 2x-y=11;x+3y=-5 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}2x-y=11\\x+3y=-5\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}y=-11+2x\\x+3y=-5\end{array}\right.\) - step2: Substitute the value of \(y:\) \(x+3\left(-11+2x\right)=-5\) - step3: Simplify: \(7x-33=-5\) - step4: Move the constant to the right side: \(7x=-5+33\) - step5: Add the numbers: \(7x=28\) - step6: Divide both sides: \(\frac{7x}{7}=\frac{28}{7}\) - step7: Divide the numbers: \(x=4\) - step8: Substitute the value of \(x:\) \(y=-11+2\times 4\) - step9: Calculate: \(y=-3\) - step10: Calculate: \(\left\{ \begin{array}{l}x=4\\y=-3\end{array}\right.\) - step11: Check the solution: \(\left\{ \begin{array}{l}x=4\\y=-3\end{array}\right.\) - step12: Rewrite: \(\left(x,y\right) = \left(4,-3\right)\) The solution to the system of linear equations is \( (x, y) = (4, -3) \). Therefore, the \( x \)-value in the solution is \( x = 4 \).