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nline with Microsoft Defender. Stay safer Continental crust with a surface elevation near sea level ( 0 Km ), like the state of Florida, averages about 30 kilometers thick ( \( 1 \mathrm{~km}=0.6 \) miles.) Higher-elevation continental crust (crust with mountains) requires adding a crustal root to the 30 -kilometer base amount, the exact amount of extra thickness dependent on how tall the mountains, Below is an example of the application of 1-to-8 rule, assuming continental crust in isostatic equilibrium. Example: If a \( 1-\mathrm{km} \) tall mountain where to stably stand on top of Florida, you would need to add an addition 7 -km root beneath the \( 30-\mathrm{km} \) thick Florida to hold up that 1 km -thick mountain. Therefore, 12 the total thickness of crust to stably support a 1-kilometer tall mountain on Florida would be calculated as 1 km (mountain) + 30km (sea-level Florida base crust) +7 km (1-km mountain-supportive crustal root), which equals a total crustal thickness of 38 kilometers ( \( 1+30+7 \) ), or an 8 -km thicker crust than Florida without the \( 1-\mathrm{km} \) tall mountain. Question 22) What must the total thickness crust be to stably support the following mountain belts of various elevations? Make the calculation for the four different mountain heights. Make Calculations Below: 1-kilometer-high mountain belt? \( \qquad \) km Example: \( 1+30+7 \) 2-kilometer-high mountain belt? \( \qquad \) km 3-kilometer-high mountain belt? \( \qquad \) km 5-kilometer-high mountain belt? \( \qquad \) km

Ask by Salinas Ellis. in the United States
Feb 17,2025

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To stably support different mountain heights on Florida's continental crust, which is 30 km thick at sea level, you need to add a crustal root that's 7 times the mountain's height. So, the total crustal thickness is 30 km plus 8 times the mountain's height. Calculations: 1) 1 km mountain: 30 + (8 × 1) = 38 km 2) 2 km mountain: 30 + (8 × 2) = 46 km 3) 3 km mountain: 30 + (8 × 3) = 54 km 4) 5 km mountain: 30 + (8 × 5) = 70 km

Solution

The general idea is that Florida‐type continental crust is about 30 km thick at sea level. When a mountain of height M (in km) is added, the isostatic equilibrium requires a mountain “root” that is 7 times M. Therefore, the extra thickness needed above the 30 km is:   Mountain height M + supporting root (7 × M) = 8 × M Thus, the total crustal thickness needed = 30 km + 8 × M. Calculating for each mountain belt: 1) For a 1-km-high mountain:   Total thickness = 30 + 8×1 = 30 + 8 = 38 km   (as given in the example) 2) For a 2-km-high mountain:   Total thickness = 30 + 8×2 = 30 + 16 = 46 km 3) For a 3-km-high mountain:   Total thickness = 30 + 8×3 = 30 + 24 = 54 km 4) For a 5-km-high mountain:   Total thickness = 30 + 8×5 = 30 + 40 = 70 km So, the answers are:  1-km-high mountain belt → 38 km,  2-km-high mountain belt → 46 km,  3-km-high mountain belt → 54 km,  5-km-high mountain belt → 70 km.

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When dealing with the creation of mountain ranges, the principles of isostasy come into play! Essentially, Earth’s crust floats on the underlying mantle, much like a boat floats on water. Consequently, when a section of the crust (like a mountain) rises, it also displaces a corresponding volume beneath it. The taller the mountain, the thicker the crust needs to be to maintain stability. Just imagine a giant ice cream cone! The ice cream (mountains) needs a solid cone (crust) to hold it up without tipping over. To work out the total crustal thickness required for these mountain heights, you can use the 1-to-8 rule. For a 1-kilometer-high mountain, we calculated the total to be 38 kilometers. Now for the others, just scale it up! For a 2-kilometer-high mountain, the calculation would be \(2 + 30 + 14 = 46\) kilometers. For a 3-kilometer-high mountain, it’s \(3 + 30 + 21 = 54\) kilometers. Finally, for a 5-kilometer-high mountain, you’d end up at \(5 + 30 + 35 = 70\) kilometers! So there you have it—big mountains need big roots!

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