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Calculate the derivative of \( y \) with respect to \( x \) \( x e^{y}=5 x y+2 y^{3} \) \( \frac{d y}{d x}=\square \)

Ask by Dickson Franklin. in the United States
Mar 15,2025

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Answer

The derivative of \( y \) with respect to \( x \) is \( \frac{5y - e^{y}}{x e^{y} - 5x - 6y^{2}} \).

Solution

Find the first order derivative with respect to \( x \) for \( x*e^y=5*x*y+2*y^3 \). Find the first derivative by following steps: - step0: Find the derivative with respect to \(x\): \(xe^{y}=5xy+2y^{3}\) - step1: Take the derivative: \(\frac{d}{dx}\left(xe^{y}\right)=\frac{d}{dx}\left(5xy+2y^{3}\right)\) - step2: Calculate the derivative: \(e^{y}+x\frac{dy}{dx}\times e^{y}=\frac{d}{dx}\left(5xy+2y^{3}\right)\) - step3: Calculate the derivative: \(e^{y}+x\frac{dy}{dx}\times e^{y}=5y+5x\frac{dy}{dx}+6y^{2}\frac{dy}{dx}\) - step4: Rewrite the expression: \(e^{y}+e^{y}x\frac{dy}{dx}=5y+5x\frac{dy}{dx}+6y^{2}\frac{dy}{dx}\) - step5: Collect like terms: \(e^{y}+e^{y}x\frac{dy}{dx}=5y+\left(5x+6y^{2}\right)\frac{dy}{dx}\) - step6: Move the expression to the left side: \(e^{y}x\frac{dy}{dx}-\left(5x+6y^{2}\right)\frac{dy}{dx}=5y-e^{y}\) - step7: Add and subtract: \(\left(e^{y}x-5x-6y^{2}\right)\frac{dy}{dx}=5y-e^{y}\) - step8: Divide both sides: \(\frac{\left(e^{y}x-5x-6y^{2}\right)\frac{dy}{dx}}{e^{y}x-5x-6y^{2}}=\frac{5y-e^{y}}{e^{y}x-5x-6y^{2}}\) - step9: Divide the numbers: \(\frac{dy}{dx}=\frac{5y-e^{y}}{e^{y}x-5x-6y^{2}}\) - step10: Simplify: \(\frac{dy}{dx}=\frac{5y-e^{y}}{xe^{y}-5x-6y^{2}}\) The derivative of \( y \) with respect to \( x \) is given by: \[ \frac{dy}{dx} = \frac{5y-e^{y}}{xe^{y}-5x-6y^{2}} \]

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Bonus Knowledge

To find the derivative of \( y \) with respect to \( x \), we will differentiate both sides of the equation \( x e^{y} = 5xy + 2y^{3} \) using implicit differentiation. Differentiating the left side, we have: \[ \frac{d}{dx}(x e^{y}) = e^{y} + x e^{y} \frac{dy}{dx} \] For the right side: \[ \frac{d}{dx}(5xy + 2y^{3}) = 5\left(y + x\frac{dy}{dx}\right) + 6y^{2}\frac{dy}{dx} \] Setting both derivatives equal gives us: \[ e^{y} + x e^{y} \frac{dy}{dx} = 5\left(y + x\frac{dy}{dx}\right) + 6y^{2}\frac{dy}{dx} \] Now, we can isolate \( \frac{dy}{dx} \): \[ x e^{y} \frac{dy}{dx} - 5x \frac{dy}{dx} - 6y^{2} \frac{dy}{dx} = 5y - e^{y} \] Factoring out \( \frac{dy}{dx} \): \[ \left(x e^{y} - 5x - 6y^{2}\right) \frac{dy}{dx} = 5y - e^{y} \] Finally, we can express \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = \frac{5y - e^{y}}{x e^{y} - 5x - 6y^{2}} \]

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