Question
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5.4 Karabo and John are at the same rest stop alongside a highway. Karabo started driving along the highway at a constant speed of \( 80 \mathrm{~km} / \mathrm{h} \). An hour later, John started driving along the same highway in the same direction as Karabo at the constant speed of \( 100 \mathrm{~km} / \mathrm{h} \). How long will it take John to catch up with Karabo?

Ask by Chambers Donnelly. in South Africa
Mar 10,2025

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Tutor-Verified Answer

Answer

John will catch up with Karabo after 4 hours.

Solution

**Step 1: Define variables** Let \( t \) be the time (in hours) after John starts when he catches up with Karabo. **Step 2: Express distances** - Karabo has been driving for \( t + 1 \) hours (John started 1 hour later). Her distance is: \[ 80(t+1) \] - John's distance is: \[ 100t \] **Step 3: Set distances equal** At the moment John catches up, the distances are equal: \[ 100t = 80(t+1) \] **Step 4: Solve the equation** Distribute on the right side: \[ 100t = 80t + 80 \] Subtract \( 80t \) from both sides: \[ 20t = 80 \] Divide both sides by 20: \[ t = 4 \] **Answer** John will catch up with Karabo after \(4\) hours.

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To determine how long it will take John to catch up with Karabo, we first need to find out how far Karabo has traveled by the time John starts driving. Since he started an hour earlier at a speed of \(80 \mathrm{~km/h}\), he has traveled: \[ \text{Distance (Karabo)} = \text{Speed} \times \text{Time} = 80 \mathrm{~km/h} \times 1 \mathrm{~h} = 80 \mathrm{~km} \] Now, let's denote the time it takes for John to catch up with Karabo as \(t\) hours after John has started driving. During this time, John will cover a distance equal to: \[ \text{Distance (John)} = 100 \mathrm{~km/h} \times t \] In that same amount of time \(t\), Karabo will continue driving and cover additional distance: \[ \text{Distance (Karabo, after John's start)} = 80 \mathrm{~km/h} \times t \] To find out when John catches up to Karabo, we set the total distance traveled by John equal to the distance Karabo traveled plus the initial distance he had: \[ 100t = 80 + 80t \] Now, solve for \(t\): \[ 100t - 80t = 80 \] \[ 20t = 80 \] \[ t = \frac{80}{20} = 4 \] Therefore, it will take John 4 hours to catch up with Karabo.

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