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To tackle \( 9 \frac{3}{16} - 7 \frac{5}{8} \), it's helpful to convert both mixed numbers to improper fractions. First, \( 9 \frac{3}{16} \) converts to \( \frac{9 \times 16 + 3}{16} = \frac{144 + 3}{16} = \frac{147}{16} \). Next, \( 7 \frac{5}{8} \) converts to \( \frac{7 \times 8 + 5}{8} = \frac{56 + 5}{8} = \frac{61}{8} \). To subtract these two fractions, we need a common denominator, which would be 16. Convert \( \frac{61}{8} \) to a denominator of 16: \( \frac{61}{8} = \frac{61 \times 2}{8 \times 2} = \frac{122}{16} \). Now, subtract the fractions: \( \frac{147}{16} - \frac{122}{16} = \frac{147 - 122}{16} = \frac{25}{16} \). This can be expressed as \( 1 \frac{9}{16} \) in mixed number form. So, \( 9 \frac{3}{16} - 7 \frac{5}{8} = 1 \frac{9}{16} \).