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Solve the following in equality e) \( \frac{3 y+2}{2}-\frac{y-6}{3}>0 \)

Ask by Chambers Gibson. in South Africa
Feb 25,2025

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Answer

\( y > -\frac{18}{7} \)

Solution

Solve the equation \( \frac{3y+2}{2}-\frac{y-6}{3}>0 \). Solve the inequality by following steps: - step0: Solve for \(y\): \(\frac{3y+2}{2}-\frac{y-6}{3}>0\) - step1: Multiply both sides: \(\left(\frac{3y+2}{2}-\frac{y-6}{3}\right)\times 2\times 3>0\times 2\times 3\) - step2: Multiply the terms: \(9y+6-2y+12>0\) - step3: Simplify: \(7y+18>0\) - step4: Move the constant to the right side: \(7y>0-18\) - step5: Remove 0: \(7y>-18\) - step6: Divide both sides: \(\frac{7y}{7}>\frac{-18}{7}\) - step7: Divide the numbers: \(y>-\frac{18}{7}\) The solution to the inequality \( \frac{3y+2}{2}-\frac{y-6}{3}>0 \) is \( y > -\frac{18}{7} \).

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To solve the inequality \( \frac{3y+2}{2} - \frac{y-6}{3} > 0 \), we start by finding a common denominator, which is 6. Rewriting the inequality: \[ \frac{3(3y + 2)}{6} - \frac{2(y - 6)}{6} > 0 \] This simplifies to: \[ \frac{9y + 6 - 2y + 12}{6} > 0 \quad \Rightarrow \quad \frac{7y + 18}{6} > 0 \] Next, we multiply both sides by 6 to eliminate the fraction (remember, since 6 is positive, the direction of the inequality stays the same): \[ 7y + 18 > 0 \] Then we solve for \( y \): \[ 7y > -18 \quad \Rightarrow \quad y > -\frac{18}{7} \] Thus, the solution to the inequality is: \[ y > -\frac{18}{7} \]

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