1. \begin{tabular}{rl}\( 9 m+2=3 m-10 \) \\ \( 9 m+2 \) & \( =3 m-10 \) \\ -[] & -[]\( ] \) \\ \hline \( 6 m+2 \) & \( =-10 \) \\ -[] & -[] \\ \hline \( 6 m \) & \( =[]] \) \\ \( \frac{6 m}{[]} \) & \( =\frac{-12}{[]} \) \\ \( m \) & \( =[] \)\end{tabular}

To solve the equation \( 9m + 2 = 3m - 10 \), we start by isolating the variable \( m \). First, subtract \( 3m \) from both sides, leading to \( 6m + 2 = -10 \). Next, subtract 2 from both sides to simplify it to \( 6m = -12 \). Finally, divide both sides by 6 to find \( m = -2 \). This equation shows a fundamental algebraic principle that can help in real-world scenarios, such as financial budgeting. For instance, if you're trying to balance income and expenses, you could set income equal to expenses (just like we did with the left and right sides of the equation) and find unknowns like how much you can afford to spend based on your income. It's a powerful tool for problem-solving in life!