$$ 1.1 .1 \lim _{x \rightarrow 1}-4 $$ Drtemine the value for both of the limis given below $$ 1.2 \lim _{x \rightarrow 1} \frac{1}{x+2} $$

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Evaluate the limit by following steps:
- step0: Evaluate the limit:
  $$\lim _{x\rightarrow 1}\left(-4\right)$$
- step1: Calculate:
  $$-4$$
Calculate the limit $$ \lim_{x\rightarrow 1} \frac{1}{x+2} $$.
Evaluate the limit by following steps:
- step0: Evaluate the limit:
  $$\lim _{x\rightarrow 1}\left(\frac{1}{x+2}\right)$$
- step1: Rewrite the expression:
  $$\frac{1}{\lim _{x\rightarrow 1}\left(x+2\right)}$$
- step2: Calculate:
  $$\frac{1}{3}$$
Let's evaluate the limits step by step.

1. **First Limit:**
   $$
   \lim_{x \rightarrow 1} -4
   $$
   Since this is a constant, the limit is simply:
   $$
   -4
   $$

2. **Second Limit:**
   $$
   \lim_{x \rightarrow 1} \frac{1}{x+2}
   $$
   To evaluate this limit, we substitute $$ x = 1 $$:
   $$
   \frac{1}{1 + 2} = \frac{1}{3}
   $$

Thus, the results for the limits are:
- The first limit is $$-4$$.
- The second limit is $$\frac{1}{3}$$ or $$0.\dot{3}$$.

You can choose either representation for the second limit based on your preference.
The first limit is $$-4$$, and the second limit is $$\frac{1}{3}$$ or $$0.\dot{3}$$.

\( 1.1 .1 \lim _{x \rightarrow 1}-4 \) Drtemine the value for both of the limis given below \[ 1.2 \lim _{x \rightarrow 1} \frac{1}{x+2} \]

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