\( 1.1 .1 \lim _{x \rightarrow 1}-4 \) Drtemine the value for both of the limis given below \[ 1.2 \lim _{x \rightarrow 1} \frac{1}{x+2} \]

Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 1}\left(-4\right)\) - step1: Calculate: \(-4\) Calculate the limit \( \lim_{x\rightarrow 1} \frac{1}{x+2} \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 1}\left(\frac{1}{x+2}\right)\) - step1: Rewrite the expression: \(\frac{1}{\lim _{x\rightarrow 1}\left(x+2\right)}\) - step2: Calculate: \(\frac{1}{3}\) Let's evaluate the limits step by step. 1. **First Limit:** \[ \lim_{x \rightarrow 1} -4 \] Since this is a constant, the limit is simply: \[ -4 \] 2. **Second Limit:** \[ \lim_{x \rightarrow 1} \frac{1}{x+2} \] To evaluate this limit, we substitute \( x = 1 \): \[ \frac{1}{1 + 2} = \frac{1}{3} \] Thus, the results for the limits are: - The first limit is \(-4\). - The second limit is \(\frac{1}{3}\) or \(0.\dot{3}\). You can choose either representation for the second limit based on your preference.