What is \( (3 x-2) \) multiplied by \( \left(x^{2}+2 x+5\right) \)
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Beyond the Answer
To multiply \( (3x - 2) \) by \( (x^2 + 2x + 5) \), we use the distributive property, also known as the FOIL method for binomials. First, distribute \( 3x \): - \( 3x \cdot x^2 = 3x^3 \) - \( 3x \cdot 2x = 6x^2 \) - \( 3x \cdot 5 = 15x \) Next, distribute \( -2 \): - \( -2 \cdot x^2 = -2x^2 \) - \( -2 \cdot 2x = -4x \) - \( -2 \cdot 5 = -10 \) Now, combine all the results: \[ 3x^3 + 6x^2 + 15x - 2x^2 - 4x - 10 \] Combine like terms: \[ 3x^3 + (6x^2 - 2x^2) + (15x - 4x) - 10 \] This simplifies to: \[ 3x^3 + 4x^2 + 11x - 10 \] So, the final result is: \[ 3x^3 + 4x^2 + 11x - 10 \]