Find the quotient. \( 8 \longdiv { 3 , 8 3 5 } \)

To find the quotient of \( 3, 8 3 5 \) divided by \( 8 \), we can set it up as a long division problem. First, consider how many times \( 8 \) can fit into \( 3 \). It doesn't fit, so we move to the next digits, making it \( 38 \). \( 8 \) goes into \( 38 \) four times because \( 8 \times 4 = 32 \). We subtract \( 32 \) from \( 38 \), leaving \( 6 \). Next, we bring down the \( 3 \) to make it \( 63 \). Now, \( 8 \) fits into \( 63 \) seven times since \( 8 \times 7 = 56 \). Subtract \( 56 \) from \( 63 \) to get \( 7 \). Now, bring down the \( 5 \) to make it \( 75 \). Finally, \( 8 \) goes into \( 75 \) nine times, because \( 8 \times 9 = 72 \). After subtracting \( 72 \) from \( 75 \), we have a remainder of \( 3 \). So, the result of the division is \( 4 7 9 \) with a remainder of \( 3 \). Therefore, the quotient is \( 479 \) and we can express this as: \( 3, 8 3 5 \div 8 = 479 \) remainder \( 3 \).