Solve for \( v \). \[ \frac{4}{v+4}=\frac{8}{2 v+8}-3 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution". \[ v=\square \]

To solve the equation \[ \frac{4}{v+4} = \frac{8}{2v+8} - 3, \] we start by simplifying the right side. Notice that \( 2v + 8 \) can be factored to \( 2(v + 4) \). Thus, we rewrite the equation as follows: \[ \frac{4}{v + 4} = \frac{8}{2(v + 4)} - 3. \] This further simplifies to: \[ \frac{4}{v + 4} = \frac{4}{v + 4} - 3. \] Now, if we let \( x = \frac{4}{v + 4} \), the right side becomes \( x - 3 \). Setting the two sides equal gives us: \[ x = x - 3. \] Subtracting \( x \) from both sides results in: \[ 0 = -3, \] which is a contradiction. This means there are no values of \( v \) that satisfy the original equation. Thus, the final answer is: \[ v=\text{No solution} \]