Question
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Franco practices the piano for \( 4 \frac{1}{2} \) hours each week. He plays soccer for \( 1 \frac{3}{4} \) hours. How much longer does Franco practice piano than play soccer?

Ask by Williams Lang. in the United States
Mar 12,2025

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Answer

Franco practices piano for \(2 \frac{3}{4}\) hours longer than he plays soccer.

Solution

1. Convert the mixed numbers to improper fractions: - For piano practice: \(4 \frac{1}{2} = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2}\) - For soccer: \(1 \frac{3}{4} = 1 + \frac{3}{4} = \frac{4}{4} + \frac{3}{4} = \frac{7}{4}\) 2. Subtract the soccer hours from the piano hours: - Write \(\frac{9}{2}\) with a denominator of 4: \(\frac{9}{2} = \frac{18}{4}\) - Compute the difference: \(\frac{18}{4} - \frac{7}{4} = \frac{11}{4}\) 3. Convert \(\frac{11}{4}\) to a mixed number: - Divide: \(11 \div 4 = 2\) with a remainder of \(3\). Thus, \(\frac{11}{4} = 2 \frac{3}{4}\) Franco practices piano \(2 \frac{3}{4}\) hours longer than he plays soccer.

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To find out how much longer Franco practices piano compared to playing soccer, we first convert the mixed numbers to improper fractions. For piano practice: \[ 4 \frac{1}{2} = \frac{9}{2} \text{ hours} \] For soccer: \[ 1 \frac{3}{4} = \frac{7}{4} \text{ hours} \] Now, we need a common denominator to subtract the two times. The least common multiple of 2 and 4 is 4. We convert \( \frac{9}{2} \) to have a denominator of 4: \[ \frac{9}{2} = \frac{18}{4} \] Now we can subtract the two fractions: \[ \frac{18}{4} - \frac{7}{4} = \frac{11}{4} \] Converting \( \frac{11}{4} \) back to a mixed number gives: \[ 11 \div 4 = 2 \text{ remainder } 3 \] So, \( \frac{11}{4} = 2 \frac{3}{4} \). Therefore, Franco practices piano \( 2 \frac{3}{4} \) hours longer than he plays soccer.

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