\( \left. \begin{array} { | l } \hline \text { Subtract the following numbers. } \\ { } \\ { 8 2 7 . 0 8 } \\ { - 162.97 } \end{array} \right. \)

To subtract \( 162.97 \) from \( 827.08 \), let’s line up the numbers by their decimal points: ``` 827.08 - 162.97 ``` Now, we can perform the subtraction starting from the rightmost digit: 1. In the hundredths place, \( 8 - 7 = 1 \). 2. In the tenths place, \( 0 - 9 \) requires borrowing. So we borrow 1 from the ones place, making it \( 10 - 9 = 1 \) (the 7 in the ones place becomes 6). 3. In the ones place, now we have \( 6 - 2 = 4 \). 4. In the tens place, \( 2 - 6 \) also requires borrowing, making it \( 12 - 6 = 6 \) (the 8 in the hundreds place becomes 7). 5. Finally, in the hundreds place, \( 7 - 1 = 6 \). So, putting it all together: ``` 827.08 - 162.97 --------- 664.11 ``` The result of the subtraction is \( 664.11 \).