The function \( f(x)=15 x \) is one-to-one. a. Find an equation for \( f^{-1}(x) \), the inverse function. b. Verify that your equation is correct by showing that \( f\left(f^{-1}(x)\right)=x \) and \( f^{-1}(f(x))=x \).
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Mind Expander
To find the inverse function \( f^{-1}(x) \) for \( f(x) = 15x \), we start by replacing \( f(x) \) with \( y \): \[ y = 15x. \] Next, we solve for \( x \) in terms of \( y \): \[ x = \frac{y}{15}. \] Thus, the inverse function is: \[ f^{-1}(x) = \frac{x}{15}. \] Now, let’s verify that \( f\left(f^{-1}(x)\right) = x \): 1. Calculate \( f\left(f^{-1}(x)\right) \): \[ f\left(f^{-1}(x)\right) = f\left(\frac{x}{15}\right) = 15\left(\frac{x}{15}\right) = x. \] 2. Next, calculate \( f^{-1}(f(x)) \): \[ f^{-1}(f(x)) = f^{-1}(15x) = \frac{15x}{15} = x. \] Since both identities hold true, we have verified that the inverse function is correct.