Question
a) \( 6 \% \) of 250 b) \( 88 \% \) of 40 c) \( 120 \% \) of 58 4. Jack, Sam and Pandu wrote three different Maths tests on Monday. Jack got 5 out of 10 for his test. Sam got 22 out of 40 for his test, and Pandu got 12 out of 20 . By converting the fractions into percentages, determine who achieved the best score. 5. Jeripo has two milk cartons. One contains 5 g of fat per 80 ml and the other contains 12 g of fat per 200 ml of milk. Express the fat content per carton as a percentage. Which carton contains less fat? 6. Maresa earns R20 000 per month. She decides to invest \( \frac{1}{10} \) of her money at \( 8 \% \) simple interest per year. a) What amount does she invest? b) How much interest will she earn at the end of the year? c) How much money will be in her investment after 5 years?
Ask by Franklin Thornton. in South Africa
Mar 11,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
- a) 6% of 250 is 15
- b) 88% of 40 is 35.2
- c) 120% of 58 is 69.6
- Pandu achieved the best score with 60%
- The second milk carton contains less fat at 6%
- Maresa invests R2000
- She earns R160 in interest each year
- After 5 years, her investment grows to R2800
Solution
Calculate the value by following steps:
- step0: Calculate:
\(0.88\times 40\)
- step1: Multiply the numbers:
\(35.2\)
Calculate or simplify the expression \( 20000 * (1/10) * (1 + 0.08 * 5) \).
Calculate the value by following steps:
- step0: Calculate:
\(20000\times \frac{1}{10}\left(1+0.08\times 5\right)\)
- step1: Multiply the numbers:
\(20000\times \frac{1}{10}\left(1+0.4\right)\)
- step2: Add the numbers:
\(20000\times \frac{1}{10}\times 1.4\)
- step3: Multiply the terms:
\(2000\times 1.4\)
- step4: Multiply the numbers:
\(2800\)
Calculate or simplify the expression \( (22/40) * 100 \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(\frac{22}{40}\right)\times 100\)
- step1: Reduce the fraction:
\(\frac{11}{20}\times 100\)
- step2: Reduce the numbers:
\(11\times 5\)
- step3: Multiply the numbers:
\(55\)
Calculate or simplify the expression \( (12/20) * 100 \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(\frac{12}{20}\right)\times 100\)
- step1: Reduce the fraction:
\(\frac{3}{5}\times 100\)
- step2: Reduce the numbers:
\(3\times 20\)
- step3: Multiply the numbers:
\(60\)
Calculate or simplify the expression \( (12/200) * 100 \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(\frac{12}{200}\right)\times 100\)
- step1: Reduce the fraction:
\(\frac{3}{50}\times 100\)
- step2: Reduce the numbers:
\(3\times 2\)
- step3: Multiply the numbers:
\(6\)
Calculate or simplify the expression \( 1.2 * 58 \).
Calculate the value by following steps:
- step0: Calculate:
\(1.2\times 58\)
- step1: Multiply the numbers:
\(69.6\)
Calculate or simplify the expression \( (5/80) * 100 \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(\frac{5}{80}\right)\times 100\)
- step1: Reduce the fraction:
\(\frac{1}{16}\times 100\)
- step2: Reduce the numbers:
\(\frac{1}{4}\times 25\)
- step3: Multiply:
\(\frac{25}{4}\)
Calculate or simplify the expression \( 0.06 * 250 \).
Calculate the value by following steps:
- step0: Calculate:
\(0.06\times 250\)
- step1: Multiply the numbers:
\(15\)
Calculate or simplify the expression \( 20000 * (1/10) \).
Calculate the value by following steps:
- step0: Calculate:
\(20000\times \frac{1}{10}\)
- step1: Reduce the numbers:
\(2000\times 1\)
- step2: Simplify:
\(2000\)
Calculate or simplify the expression \( (5/10) * 100 \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(\frac{5}{10}\right)\times 100\)
- step1: Reduce the fraction:
\(\frac{1}{2}\times 100\)
- step2: Reduce the numbers:
\(1\times 50\)
- step3: Simplify:
\(50\)
Calculate or simplify the expression \( (20000 * (1/10)) * (0.08) \).
Calculate the value by following steps:
- step0: Calculate:
\(\left(20000\times \frac{1}{10}\right)\times 0.08\)
- step1: Remove the parentheses:
\(20000\times \frac{1}{10}\times 0.08\)
- step2: Multiply the terms:
\(2000\times 0.08\)
- step3: Multiply the numbers:
\(160\)
Let's solve each part step by step.
### Part a: Calculate Percentages
1. **\( 6\% \) of 250:**
\[
6\% \text{ of } 250 = 0.06 \times 250 = 15
\]
2. **\( 88\% \) of 40:**
\[
88\% \text{ of } 40 = 0.88 \times 40 = 35.2
\]
3. **\( 120\% \) of 58:**
\[
120\% \text{ of } 58 = 1.2 \times 58 = 69.6
\]
### Part b: Determine Best Score
- **Jack's Score:**
\[
\text{Percentage} = \left(\frac{5}{10}\right) \times 100 = 50\%
\]
- **Sam's Score:**
\[
\text{Percentage} = \left(\frac{22}{40}\right) \times 100 = 55\%
\]
- **Pandu's Score:**
\[
\text{Percentage} = \left(\frac{12}{20}\right) \times 100 = 60\%
\]
**Conclusion:** Pandu achieved the best score with \( 60\% \).
### Part c: Fat Content in Milk Cartons
1. **First Carton:**
\[
\text{Fat content} = \left(\frac{5}{80}\right) \times 100 = 6.25\%
\]
2. **Second Carton:**
\[
\text{Fat content} = \left(\frac{12}{200}\right) \times 100 = 6\%
\]
**Conclusion:** The second carton contains less fat at \( 6\% \).
### Part d: Maresa's Investment
1. **Amount Invested:**
\[
\text{Amount} = 20000 \times \frac{1}{10} = 2000
\]
2. **Interest Earned in One Year:**
\[
\text{Interest} = 2000 \times 0.08 = 160
\]
3. **Total Amount After 5 Years:**
\[
\text{Total Amount} = 2000 \times \left(1 + 0.08 \times 5\right) = 2000 \times 1.4 = 2800
\]
### Summary of Results
- a) \( 6\% \) of 250 = 15
- b) \( 88\% \) of 40 = 35.2
- c) \( 120\% \) of 58 = 69.6
- Best Score: Pandu with \( 60\% \)
- Fat Content: First Carton = \( 6.25\% \), Second Carton = \( 6\% \) (Second carton has less fat)
- Investment Amount: R2000
- Interest Earned: R160
- Total After 5 Years: R2800
Answered by UpStudy AI and reviewed by a Professional Tutor
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Bonus Knowledge
Jack, Sam, and Pandu's scores can be calculated as follows: Jack scored \(50\%\) on his test (5 out of 10), Sam scored \(55\%\) (22 out of 40), and Pandu scored \(60\%\) (12 out of 20). Therefore, Pandu achieved the best score with \(60\%\)! Now, for the fat content: the first carton has \(6.25\%\) fat (calculated as \( \frac{5}{80} \times 100 \)) while the second carton has \(6\%\) fat (calculated as \( \frac{12}{200} \times 100 \)). So, the second carton contains less fat with its \(6\%\! \) content!