A principal of $$ \$ 3900 $$ was invested at $$ 6.75 \% $$ interest, compounded annually. Let $$ t $$ be the number of years since the start of the imvestment. Let $$ y $$ be the value of the investmert im folli Write an exponential function showing the relationship betwoen $$ y $$ and $$ t $$.

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To write an exponential function that shows the relationship between the value of the investment $$ y $$ and the time in years $$ t $$, we can use the formula for compound interest:

$$
y = P(1 + r)^t
$$

where:
- $$ P $$ is the principal amount (initial investment),
- $$ r $$ is the annual interest rate (as a decimal),
- $$ t $$ is the number of years.

Given:
- $$ P = 3900 $$
- $$ r = 6.75\% = 0.0675 $$

Now, substituting the values into the formula:

$$
y = 3900(1 + 0.0675)^t
$$

This simplifies to:

$$
y = 3900(1.0675)^t
$$

Thus, the exponential function showing the relationship between $$ y $$ and $$ t $$ is:

$$
y = 3900(1.0675)^t
$$
The exponential function is $$ y = 3900(1.0675)^t $$.

A principal of was invested at interest, compounded annually.
Let be the number of years since the start of the imvestment. Let be the value of the investmert im folli
Write an exponential function showing the relationship betwoen and .

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A principal of was invested at interest, compounded annually. Let be the number of years since the start of the imvestment. Let be the value of the investmert im folli Write an exponential function showing the relationship betwoen and .