Login
Premium
Home Question Bank Math Algebra
Question
upstudy study bank question image url

(1) Scott and william are reading the same book for their English class. Scott is currently on page 150 , and willam is on page 66 . Scott reads 10 pages each day, and William reads 22 pages each day. 4i) Which equation can you use to find \( d \), the number of days it will take for William to have read as many pages as Scott? \[ 150+10 d=66+22 d \] \[ 150+22 d=66+10 d \] 4)) How many days will it take for William to have read as many pages as Scott? 4)) \( \square \) days

Ask by Lang Phillips. in the United States
Jan 10,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

4i) The equation is \( 150 + 10d = 66 + 22d \). 4ii) It will take 7 days for William to have read as many pages as Scott.

Solution

Let's solve each part of the problem step-by-step. ### 4i) **Which equation can you use to find \( d \), the number of days it will take for William to have read as many pages as Scott?** To find when William has read as many pages as Scott, set their page counts equal to each other: - **Scott's page count after \( d \) days:** \( 150 + 10d \) - **William's page count after \( d \) days:** \( 66 + 22d \) So, the equation you can use is: \[ 150 + 10d = 66 + 22d \] ### 4ii) **How many days will it take for William to have read as many pages as Scott?** Now, solve the equation for \( d \): \[ 150 + 10d = 66 + 22d \] 1. **Subtract 10d from both sides:** \[ 150 = 66 + 12d \] 2. **Subtract 66 from both sides:** \[ 84 = 12d \] 3. **Divide both sides by 12:** \[ d = 7 \] **It will take 7 days for William to have read as many pages as Scott.** --- **Final Answers:** 4i) \[ 150 + 10d = 66 + 22d \] 4ii) \( \boxed{7} \) days

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

The Deep Dive

To find how many days it will take for William to read as many pages as Scott, we can start with the equation \( 150 + 10d = 66 + 22d \). This equation sets Scott's total pages read equal to William's total pages read after \( d \) days. By rearranging the equation: 1. Subtract \( 10d \) from both sides: \( 150 = 66 + 12d \). 2. Then, isolate \( d \) by subtracting 66 from both sides: \( 84 = 12d \). 3. Finally, divide by 12: \( d = 7 \) days. So, it will take William \( 7 \) days to catch up with Scott! Now, here's something cool: Did you know that reading speed varies by book genre? People often read fiction faster than non-fiction because narratives tend to draw readers in emotionally. So, if Scott and William were reading a gripping thriller, they might finish quicker than if it were a complex textbook! Also, if they’re aiming to read more efficiently, summarizing chapters as they go can help retain the information better. Staying engaged through note-taking or discussing with each other can keep the reading experience fun and more effective!

Related Questions

3.) \( \left(a^{-2}\right)\left(-3 a^{0}\right) \)
Algebra South Africa Feb 28, 2025
Solve for \( x \) (i) \( 4^{x+1}=32 \)
Algebra Kenya Feb 28, 2025
1. \( (x+3)^{2} \) 2. \( (2 y-5)^{2} \) 3. \( (4 a+7)^{2} \) 4. \( (3 m-2 n)^{2} \) 5. \( (5 p+q)^{2} \) Desarrolla los siguientes trinomios al cuadrado usando la fórmula: 6. \( (x+y+2)^{2} \) 7. \( (2 a-b+3)^{2} \) 8. \( (m+2 n-5)^{2} \) 9. \( (3 p+q-4)^{2} \) 10. \( (x-2 y+z)^{2} \)
Algebra Mexico Feb 28, 2025
Ejorclelos do rofuerzo: Smplicea las slguientes expreslones elgebralcas reduden ios himinaz cmen sean semejantes 1) \( x+2 x= \) 6) \( 70-4 a+96 \) 2) \( 3 y-y= \) 7) \( 2 y+3 y-y+6 y \) 3) \( 5 m+3 p= \) 8) \( 5 m+8 n-3 m+2 n= \) 4) \( 4 m n+5 m n= \) 9) \( 4 p-7 q+2 p+5 q= \) 5) \( m^{2}+3 m= \) 10) \( 3 x+5 x^{2}-2 x= \) Realiza las sigulentes multiplicaciones. 11) \( x \cdot x= \) 16) \( (-4 x)(-2 y)(3 z)= \) 12) \( 3 x \cdot 4 x= \) 17) \( x^{2} \cdot 2 x= \) 13) \( 5 a(-2 a)= \) 18) \( x y \cdot x^{2}= \) 14) \( 2 y \cdot 3 y \cdot 4 y= \) 19) \( -2 x y^{3}\left(-5 x^{2}\right) \) 15) \( (3 m)(2 n)(-5 p)= \) 20) \( \left(-2 x^{3}\right)\left(-3 y^{2}\right)(-4 z) \)
Algebra Mexico Feb 28, 2025
Questions 1) \( \begin{array}{llll}\text { a) Expand } \frac{x^{5}}{x^{3}} \text { and then cancel like factors to show that } \frac{x^{5}}{x^{3}}=x^{2} \\ \text { b) Write your own question that will give an answer } m^{3} \text { when two powers are divided. } \\ \text { c) Show that } \frac{1}{\text { a.a.a.a.a }} \text { is the same as } a^{1} \div a^{6} \text {. } \\ \begin{array}{lll}\text { a) } x^{6+2} & \text { b) } x^{6-2} & \text { c) } x^{6 \div 2} \\ \text { 3) Fill in the blanks: } & \text { b) } x^{9} \div \square=x^{3} & \text { c) } x^{4} y^{2} \div x^{3}=\square y^{2}\end{array}\end{array} \begin{array}{ll}\text { a) } x^{4} \times x^{\square}=x^{9} & \text { d) } x^{6 \times 2}\end{array} \)
Algebra South Africa Feb 28, 2025

Latest Algebra Questions

Ashlee Lange Solve for \( t \). Separate multiple answers with a comma. \[ 24 t^{2}+33 t=9 t \] \( t= \)
Algebra United States Feb 28, 2025
(ii) \( \frac{81^{a x} \times 27^{x}}{9^{x}}=729 \) (iii) Find the value of \( x \) and \( y \). \( 9^{a y} \times 2^{x}=72 \) (iv) \( 3^{2 y}=81 \) Evaluate the following index expressions (i) \( 25^{3 / 2} \times 9^{3 / 3 / 2} \) in
Algebra Kenya Feb 28, 2025
5.) \( 16^{x}-1 \) \( 5 \times 4^{x}-5 \)
Algebra South Africa Feb 28, 2025
4.) \( -5 x(-2 x y z)^{0} \)
Algebra South Africa Feb 28, 2025
3.) \( \left(a^{-2}\right)\left(-3 a^{0}\right) \)
Algebra South Africa Feb 28, 2025
Prev Next
Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy