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Answer
L’inequazione
è vera quando
. Questo accade:
- Quando entrambi
e sono positivi, nel primo quadrante: e periodi successivi. - Quando entrambi
e sono negativi, nel terzo quadrante: e periodi successivi.
Quindi, la soluzione è:
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Mind Expander
To solve the inequality
, we first simplify it to
(since multiplying by -1 reverses the inequality). Knowing that
, we deduce that our inequality reduces to
. This means
must lie in intervals where the sine function is positive, which occurs in the ranges
and
.
Thus, for the original
, the solution converts to:
-
leading to -
giving
So,
values satisfying
are in
and
.