Login
Premium
Home Question Bank Math Algebra
Question
upstudy study bank question image url

Найдите значение выражения \( \frac{a^{5,96} \cdot a^{2,4}}{a^{5,36}} \) при \( a=6 \). Ответ:

Ask by Ryan Ramos. in Russia
Mar 15,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\( 216 \)

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Answered by UpStudy AI and reviewed by a Professional Tutor

Mind Expander

Чтобы найти значение выражения \( \frac{a^{5,96} \cdot a^{2,4}}{a^{5,36}} \), сначала упростим его с использованием свойств степеней: \[ \frac{a^{5,96} \cdot a^{2,4}}{a^{5,36}} = \frac{a^{5,96 + 2,4}}{a^{5,36}} = \frac{a^{8,36}}{a^{5,36}} = a^{8,36 - 5,36} = a^{3} \] Теперь подставим значение \( a = 6 \): \[ a^{3} = 6^{3} = 216 \] Таким образом, значение выражения равно 216.

Related Questions

Consider the following function. Complete parts (a) through (e) below. \( y=-2 x^{2}+8 x+5 \) The parabola opens upward. The parabola opens downward. b. Find the vertex. The vertex is (Type an ordered pair.) c. Use the quadratic formula to find the x-intercepts. The \( x \)-intercept(s) is/are (Type an integer or a decimal rounded to the nearest tenth as needed. Use a comma to separate answers as needed.) d. Find the \( y \)-intercept. The \( y \)-intercept is (Type an integer or a fraction.) e. Use the results from parts (a)-(d) to graph the quadratic s.-.
Algebra United States Mar 17, 2025
10. Prove that the set of matrices of the form \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right) \] is a group under matrix multiplication. This group, known as the Heisenberg group, is important in quantum physics. Matrix multiplication in the Heisenberg group is defined by \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{lll}1 & x^{\prime} & y^{\prime} \\ 0 & 1 & z^{\prime} \\ 0 & 0 & 1\end{array}\right)=\left(\begin{array}{ccc}1 & x+x^{\prime} & y+y^{\prime}+x z^{\prime} \\ 0 & 1 & z+z^{\prime} \\ 0 & 0 & 1\end{array}\right) \]
Algebra United States Mar 17, 2025
10. Prove that the set of matrices of the form \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right) \] is a group under matrix multiplication. This group, known as the Heisenberg group, is important in quantum physics. Matrix multiplication in the Heisenberg group is defined by \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{ccc}1 & x^{\prime} & y \\ 0 & 1 & z^{\prime} \\ 0 & 0 & 1\end{array}\right)=\left(\begin{array}{cc}1 & x+x^{\prime} \\ 0 & 1 \\ 0 & 0\end{array}\right) \]
Algebra United States Mar 17, 2025
Consider the following function. Complete parts (a) through (e) below. \( y=x^{2}+4 x+3 \) The parabola opens downward. The parabola opens upward. b. Find the vertex. The vertex is (Type an ordered pair.) c. Find the \( x \)-intercepts. The \( x \)-intercepts are (Type an integer or a fraction. Use a comma to separate answers as needed.) d. Find the \( y \)-intercept. The \( y \)-intercept is \( \square \). (Type an integer or a fraction.) e. Use the results from parts (a)-(d) to graph the quadratic function.
Algebra United States Mar 17, 2025
Demuestre que \( \left|\begin{array}{lll}1 & x & x^{2} \\ 1 & y & y^{2} \\ 1 & z & z^{2}\end{array}\right|=(x-y)(y-z)(z-x) \)
Algebra Mexico Mar 17, 2025

Latest Algebra Questions

1. Solve the formula \( P=\pi d+2 L+W+2 \pi d \) for \( d \)
Algebra United States Mar 17, 2025
Solve the formula \( P=\pi d+2 L+W+2 \pi d \) for \( d \)
Algebra United States Mar 17, 2025
10. Prove that the set of matrices of the form \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right) \] is a group under matrix multiplication. This group, known as the Heisenberg group, is important in quantum physics. Matrix multiplication in the Heisenberg group is defined by \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{lll}1 & x^{\prime} & y^{\prime} \\ 0 & 1 & z^{\prime} \\ 0 & 0 & 1\end{array}\right)=\left(\begin{array}{ccc}1 & x+x^{\prime} & y+y^{\prime}+x z^{\prime} \\ 0 & 1 & z+z^{\prime} \\ 0 & 0 & 1\end{array}\right) \]
Algebra United States Mar 17, 2025
Consider the following function. Complete parts (a) through (e) below. \( y=-2 x^{2}+8 x+5 \) The parabola opens upward. The parabola opens downward. b. Find the vertex. The vertex is (Type an ordered pair.) c. Use the quadratic formula to find the x-intercepts. The \( x \)-intercept(s) is/are (Type an integer or a decimal rounded to the nearest tenth as needed. Use a comma to separate answers as needed.) d. Find the \( y \)-intercept. The \( y \)-intercept is (Type an integer or a fraction.) e. Use the results from parts (a)-(d) to graph the quadratic s.-.
Algebra United States Mar 17, 2025
10. Prove that the set of matrices of the form \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right) \] is a group under matrix multiplication. This group, known as the Heisenberg group, is important in quantum physics. Matrix multiplication in the Heisenberg group is defined by \[ \left(\begin{array}{lll}1 & x & y \\ 0 & 1 & z \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{ccc}1 & x^{\prime} & y \\ 0 & 1 & z^{\prime} \\ 0 & 0 & 1\end{array}\right)=\left(\begin{array}{cc}1 & x+x^{\prime} \\ 0 & 1 \\ 0 & 0\end{array}\right) \]
Algebra United States Mar 17, 2025
Prev Next
Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy