There are 6 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances? \( \square \) ways (Type a whole number.)
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To find the number of different ways to schedule the performances with one specific performer (let's call this performer A) insisting on being last, we can consider the other 5 performers (B, C, D, E, and F). Since performer A is fixed in the last position, we only need to arrange the other 5 performers. The number of arrangements of 5 performers is calculated as \(5!\) (5 factorial), which is: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] Thus, there are \(120\) different ways to schedule the appearances. 120 ways