There are 6 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances? \( \square \) ways (Type a whole number.)

To find the number of different ways to schedule the performances with one specific performer (let's call this performer A) insisting on being last, we can consider the other 5 performers (B, C, D, E, and F). Since performer A is fixed in the last position, we only need to arrange the other 5 performers. The number of arrangements of 5 performers is calculated as \(5!\) (5 factorial), which is: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] Thus, there are \(120\) different ways to schedule the appearances. 120 ways